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Question

Solve:
x2x2a2dx

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Solution

x2x2a2dxLetx=asinθ1=acosθdθdxdx=acosθdθ(1)x2x2a2=a2sin2θa2sin2θa2=tan2θ(1sin2θ=cos2θandsinθcosθ=tanθ)x2x2a2dx=(tan2θ).acosθdθ=a(sec2θ1)cosθdθ(1+tan2θ=sec2θ)=a(cosθsecθ)dθ=asinθlog|secθ+tanθ|+C(secθ=log|secθ+tanθ|)x=asinθsinθ=xax2x2a2dx=a.xalogaa2x2+xa2x2+C(fromthefiguregetthevalueofsecθandtanθ)=xloga+xa2x2+C
1096472_1092217_ans_3b8c9c6657b542b9810de170e9fc782e.jpg

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