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Question

Solve:(x3+1)(x2)x2.dx

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Solution

Given the integral,
(x3+1)(x2)x2dx=x4+x2x32x2dx=[x2+1x2x2x2]dx=x2dx+1xdx2xdx21x2dx=x33+ln(|x|)2x222(1x)+C=ln(|x|)+x33x2+2x+C=ln(|x|)+x33x23+2x+C.

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