wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve:(x3+1)(x2)x2.dx

Open in App
Solution

Given the integral,
(x3+1)(x2)x2dx=x4+x2x32x2dx=[x2+1x2x2x2]dx=x2dx+1xdx2xdx21x2dx=x33+ln(|x|)2x222(1x)+C=ln(|x|)+x33x2+2x+C=ln(|x|)+x33x23+2x+C.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon