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Question

Solve xa2+x2dx

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Solution

Consider the given integral.

I=xa2+x2dx

Let t=a2+x2

dtdx=0+2x

dt2=xdx

Therefore,

I=12dtt

I=12×2t+C

I=t+C

On putting the value of t, we get

I=a2+x2+C


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