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Question

Solve ex(x2+5x+7)(x+3)2dx

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Solution

ex(x2+5x+7)(x+3)2dx

let
u2=(x+3)2

x2+5x+7=u2u+1

eu3(u2u+1)(u)2du

=e3eu(1u21u+1)du


=e3eudu+e3(1u1u2)eudu

=e3eu+e3u


=eu3+e3u


Putting the value of u, we get

=ex+e3x+3+c

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