Solve:
$\int (tan x + cot x) d x$

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Solution

Now,
$\int (tan x + cot x) d x$
$= \int (\frac{sin x}{cos x} + \frac{cos x}{sin x}) d x$
$= - log | cos x | + log | sin x | + log | c |$ [ Where $c$ is integrating constant'
$= log | c tan x |$ .

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