Question

Solve :${\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2$

Answer 1

Let $a={\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2$

$={\left(\frac{-2}{3}\right)}^{-4}$

$={\left(\frac{-3}{2}\right)}^4$

$a={\left(\frac{-3}{2}\right)}^4=\frac{81}{16}$

$\therefore {\left\{{\left(\frac{-2}{3}\right)}^{-2}\right\}}^2=\frac{81}{16}$