Solve $4 \int 2 2^{x} d x$ .

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Solution

Now,
$4 \int 2 2^{x} d x$
$= {[\frac{2^{x}}{log 2}]}_{x = 2}^{x = 4}$
$= \frac{1}{log 2} . (2^{4} - 2^{2})$
$= \frac{12}{log 2}$ .

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