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Question

Solve: π20tanxcotx+tanxdx.

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Solution

Let I= π20tanxcotx+tanxdx...…(1)
or, I= π20cotxtanx+cotxdx...…(2)
Now adding (1) and (2) we get,
2I=π20dx
or, 2I=π2
or, i=π4.

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