Solve- 2-2-3- then - -

The correct option is A nπ±5π12,n∈ I 2θ = 2/√(3) ⇒cos 2θ= √(3)/2 ⇒cos 2θ=cos5π6 ⇒ 2θ= 2nπ±5π6,n∈ I ⇒θ=nπ±5π12,n∈ I ...

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Sum of Trigonometric Ratios in Terms of Their Product

Solve: 2θ=-...

Question

Solve: $sec 2 θ = - \frac{2}{\sqrt{3}}$ , then $θ = ?$

n π \pm \frac{5 π}{12}, n \in I

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n π \pm \frac{7 π}{12}, n \in I

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n π \pm \frac{9 π}{12}, n \in I

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n π \pm \frac{3 π}{12}, n \in I

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