wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve secx1=(21)tanx

Open in App
Solution

Given, secx1=(21)tanx1+secx+tanx2tanx=0
Put y=tanx2
1y212yy21+22yy21y2y21+11y2+1y2y2+1=0
y22y+yy21=0y22y+y=0y(y1+2)=0
y=0 or y=21
tanx2=0 or tanx2=21
x=2nπ or x=2nπ+π4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon