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Question

Solve: nk(k+1)(k+2)xk

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Solution

nk=1k(k+1)(k+2)xk
nk=1(k3+3k2+2k)
S=nk=1k3+3nk=1k2+2nk=1k
S=[n(n+1)2]2+[n(n+1)(2n1)6]+[n(n+1)2]
S=n+(n+1)12(3n2+7n+4)

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