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Byju's Answer
Standard XII
Mathematics
Sum of Trigonometric Ratios in Terms of Their Product
Solve tan2 ...
Question
Solve
tan
2
x
+
(
1
−
√
3
)
tan
x
−
√
3
=
0
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Solution
Given,
tan
2
x
+
(
1
−
√
3
)
tan
x
−
√
3
=
0
⇒
tan
x
=
−
1
+
√
3
±
√
4
−
2
√
3
+
4
√
3
2
=
−
1
,
√
3
⇒
x
=
n
π
+
3
π
2
or
x
=
n
π
+
π
3
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0
Similar questions
Q.
Solve the following inequality:
tan
2
x
−
(
1
+
√
3
)
tan
x
+
√
3
>
0
Q.
Solve the following equations.
2
√
3
(
t
a
n
x
−
c
o
t
x
)
=
t
a
n
2
x
+
c
o
t
2
x
−
2.
Q.
Solve
tan
2
x
+
[
1
−
√
3
]
tan
x
−
√
3
=
0
.
Q.
Solve the following equations:
(i)
sin
2
θ
-
cos
θ
=
1
4
(ii)
2
cos
2
θ
-
5
cos
θ
+
2
=
0
(iii)
2
sin
2
x
+
3
cos
x
+
1
=
0
(iv)
4
sin
2
θ
-
8
cos
θ
+
1
=
0
(v)
tan
2
x
+
1
-
3
tan
x
-
3
=
0
(vi)
3
cos
2
θ
-
2
3
sin
θ
cos
θ
-
3
sin
2
θ
=
0
(vii)
cos
4
θ
=
cos
2
θ
Q.
Solve the following equations:
(i)
sin
2
x
-
cos
x
=
1
4
(ii)
2
cos
2
x
-
5
cos
x
+
2
=
0
(iii)
2
sin
2
x
+
3
cos
x
+
1
=
0
(iv)
4
sin
2
x
-
8
cos
x
+
1
=
0
(v)
tan
2
x
+
1
-
3
tan
x
-
3
=
0
(vi)
3
cos
2
x
-
2
3
sin
x
cos
x
-
3
sin
2
x
=
0
(vii)
cos
4
x
=
cos
2
x
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Sum of Trigonometric Ratios in Terms of Their Product
Standard XII Mathematics
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