Solve tan2 x- 1-3 tan x-3-0

Given, tan ^ 2 x+( 1 √( 3 ) #160;) tan #160;x √( 3 ) =0 #160;⇒tan x = 1+√( 3 )±√( 4 2√( 3 ) +4√( 3 ) #160;) #160;/ 2 = 1,√( 3 ) #160; ...

334

You visited us 334 times! Enjoying our articles? Unlock Full Access!

Sum of Trigonometric Ratios in Terms of Their Product

Solve tan2 ...

Question

Solve ${tan}^{2} x + (1 - \sqrt{3}) tan x - \sqrt{3} = 0$

Open in App

Solution

Suggest Corrections

Similar questions

{tan}^{2} x - (1 + \sqrt{3}) tan x + \sqrt{3} > 0

\frac{2}{\sqrt{3}} (t a n x - c o t x) = t a n^{2} x + c o t^{2} x - 2.

{tan}^{2} x + [1 - \sqrt{3}] tan x - \sqrt{3} = 0

\sin^{2} θ - \cos θ = \frac{1}{4}

2 \cos^{2} θ - 5 \cos θ + 2 = 0

2 \sin^{2} x + \sqrt{3} \cos x + 1 = 0

4 \sin^{2} θ - 8 \cos θ + 1 = 0

\tan^{2} x + (1 - \sqrt{3}) \tan x - \sqrt{3} = 0

3 \cos^{2} θ - 2 \sqrt{3} \sin θ \cos θ - 3 \sin^{2} θ = 0

\cos 4 θ = \cos 2 θ

\sin^{2} x - \cos x = \frac{1}{4}

2 \cos^{2} x - 5 \cos x + 2 = 0

2 \sin^{2} x + \sqrt{3} \cos x + 1 = 0

4 \sin^{2} x - 8 \cos x + 1 = 0

\tan^{2} x + (1 - \sqrt{3}) \tan x - \sqrt{3} = 0

3 \cos^{2} x - 2 \sqrt{3} \sin x \cos x - 3 \sin^{2} x = 0

\cos 4 x = \cos 2 x

Join BYJU'S Learning Program