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Question

Solve tanθtan4θ=1 for 0<θ<π

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Solution

Given, tanθtan4θ=1sinθsin4θ=cosθcos4θcosθcos4θsinθsin4θ=0cos(θ+4θ)=0cos5θ=0
5θ=(2n+1)π2θ=(2n+1)π10

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