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Question

Solve limθπ42cosθsinθ(4θπ)2 is 1b2. Find b.

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Solution

cosθ+sinθ=2cos(θπ/4)
Substitute (θπ/4)=x
limx02(1cosx)16x2=limx02216sin2(x/2)x2
=142.14.1=1162
Ans: 16

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