Question

Solve:

$e^{2x}\cos ydx=e^x\sin ydy$

Answer 1

Given the differential equation,

$e^{2x}\cos ydx=e^x\sin ydy$

or, $e^{x}dx=\tan ydy$

Now integrating both sides we get,

$e^x=\log |\sec x|+c$. [ Where $c$ is integrating constant]