e^ log e^2 =e^log e^ 2 #160; #160; [∵ alog b=log b^0] =e^ 2log e =e^ 2× 0.4342 #160; #160; #160; [∵log_10e=0.4342] ...

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Solve: e - l...

Question

Solve:
$e^{- log e^{2}}$

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Solution

$e^{- log e^{2}}$
$= e^{log e^{- 2}}$ $[∵ a log b = log b^{0}]$
$= e^{- 2 log e}$
$= e^{- 2 \times 0.4342}$ $[∵ {log}_{10} e = 0.4342]$
$= e^{- 0.8684}$

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