Question

Solve each equation using trial and error method

$4z+2=10$

Answer 1

Solving equation using trial and error method

$z$	$LHS$	$RHS$
$0$	$4z+2=(4\times 0)+2=0+2=2$	$10$	$LHS\ne RHS$
$1$	$4z+2=(4\times 1)+2=4+2=6$	$10$	$LHS\ne RHS$
$2$	$4z+2=(4\times 2)+2=8+2=10$	$10$	$LHS=RHS$
$3$	$4z+2=(4\times 3)+2=12+2=14$	$10$	$LHS\ne RHS$

From the table, we find that $LHS=RHS$ when $z=2$

Hence, the solution of given equation is $z=2$