Question

Solve each equation using trial and error method

$5b+6=11$

Answer 1

Solving equation using trial and error method

$b$	$LHS$	$RHS$
$0$	$5b+6=(5\times 0)+6=0+6=6$	$11$	$LHS\ne RHS$
$1$	$5b+6=(5\times 1)+6=5+6=11$	$11$	$LHS=RHS$
$2$	$5b+6=(5\times 2)+6=10+6=16$	$11$	$LHS\ne RHS$
$3$	$5b+6=(5\times 3)+6=15+6=21$	$11$	$LHS\ne RHS$

From the table, we find that $LHS=RHS$ when $b=1$

Hence, the solution of given equation is $b=1$