Solve each equation using trial and error method
$7 x + 4 = 11$

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Solution

Solving equation using trial and error method
$y$
$L H S$
$R H S$

$0$
$7 x + 4 = (7 \times 0) + 4 = 4$
$11$
$L H S \neq R H S$
$1$
$7 x + 4 = (7 \times 1) + 4 = 11$
$11$
$L H S = R H S$
$2$
$7 x + 4 = (7 \times 2) + 4 = 18$
$11$
$L H S \neq R H S$
$3$
$7 x + 4 = (7 \times 3) + 4 = 25$
$11$
$L H S \neq R H S$
From the table, we find that $L H S = R H S$ when $y = 1$
Hence, the solution of given equation is $y = 1$

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