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Byju's Answer
Standard X
Mathematics
Common Difference
Solve each of...
Question
Solve each of the following Cryptarithms:
3
7
+
A
B
9
A
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Solution
Two
possible
values
of
A
are
:
(
i
)
If
7
+
B
≤
9
∴
3
+
A
=
9
⇒
A
=
6
But
if
A
=
6
,
7
+
B
must
be
larger
than
9
.
Hence
,
it
is
impossible
.
(
ii
)
If
7
+
B
≥
9
∴
1
+
3
+
A
=
9
⇒
A
=
5
If
A
=
5
and
7
+
B
=
5
,
B
must
be
8
∴
A
=
5
,
B
=
8
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1
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