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Question

Solve each of the following Cryptarithms:
37+AB 9A

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Solution

Two possible values of A are:(i) If 7 + B 9 3 + A = 9 A = 6But if A = 6, 7 + B must be larger than 9. Hence, it is impossible.(ii) If 7 + B 9 1 + 3 + A = 9 A = 5If A = 5 and 7 + B = 5, B must be 8 A = 5, B = 8

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