Question

Solve each of the following equation and also check your result in each case:
$\frac{7y+2}{5}=\frac{6y-5}{11}$

Answer 1

$$\begin{gathered} \frac{7\mathrm{y}+2}{5}=\frac{6\mathrm{y}-5}{11} \\ \mathrm{or}77\mathrm{y}+22=30\mathrm{y}-25 \\ \mathrm{or}77\mathrm{y}-30\mathrm{y}=-25-22 \\ \mathrm{or}47\mathrm{y}=-47 \\ \mathrm{or}\mathrm{y}=\frac{-47}{47}=-1 \\ \mathrm{Verification}: \\ \mathrm{L}.\mathrm{H}.\mathrm{S}.=\frac{-7+2}{5}=\frac{-5}{5}=-1 \\ \mathrm{R}.\mathrm{H}.\mathrm{S}.=\frac{-6-5}{11}=\frac{-11}{11}=-1 \end{gathered}$$

$\therefore$ L.H.S. = R.H.S. for y = $-$1