Question

Solve each of the following equation by using the method of completing the square:
$3x^2-2x-1=0$

Answer 1

Given,

$3x^2-2x-1=0$

$3x^2-3x+x-1=0$

$3x(x-1)+1(x-1)=0$

$(x-1)(3x+1)=0$

$\therefore x=1,-\frac{1}{3}$