Question

Solve each of the following equation by using the method of completing the square:
$\frac{2}{x^2}-\frac{5}{x}+2=0$

Answer 1

Given,

$\frac{2}{x^2}-\frac{5}{x}+2=0$

$2-5x+2x^2=0$

$2x^2-5x+2=0$

$2x^2-4x-x+2=0$

$2x(x-2)-1(x-2)=0$

$(x-2)(2x-1)=0$

$\therefore x=2,\frac{1}{2}$