Question

Solve each of the following equations. Also, verify the result in each case.
3(x − 3) = 5(2x + 1)

Answer 1

6. 3(x − 3) = 5(2x + 1)
On expanding the brackets on both sides, we get
=> $3\times x-3\times 3=5\times 2x+5\times 1$
=> 3x $-$ 9 = 10x + 5
Transposing 10x to LHS and 9 to RHS, we get
=> 3x $-$ 10x = 9 + 5
=> $-$7x = 14
Dividing both sides by 7, we get
=> $\frac{-7\mathrm{x}}{7}=\frac{14}{7}$
=> x = $-$2
Verification:
Substituting x = $-$2 on both sides, we get
$3\left(-2-3\right)=5\left(2\left(-2\right)+1\right)$
$3\left(-5\right)=5\left(-3\right)$
$-$15 = $-$15
LHS = RHS
Hence, verified.