Question

Solve each of the following equations. Also, verify the result in each case.
3x − 2 (2x − 5) = 2(x + 3) − 8

Answer 1

3x − 2 (2x − 5) = 2(x + 3) − 8
On expanding the brackets on both sides, we get
=> $3x-2\times 2x+2\times 5=2\times x+2\times 3-8$
=> $3x-4x+10=2x+6-8$
=> $-x+10=2x-2$
Transposing x to RHS and 2 to LHS, we get
=> 10 + 2 = 2x + x
=> 3x = 12
Dividing both sides by 3, we get
=> $\frac{3x}{3}=\frac{12}{3}$
=> x = 4
Verification:
Substituting x = 4 on both sides, we get
$3\left(4\right)-2\left(2\left(4\right)-5\right)=2\left(4+3\right)-8$
12$-$2 (8 $-$ 5) = 14$-$8
12 $-$ 6 = 6
6 = 6
LHS = RHS
Hence, verified.