Given : 5(7x+5)3−233=13−4x−23
35x+253+4x−23=13+233
35x+25+4x−23=39+233
39x+233=623
39x + 23 = 62
39x = 62 - 23
39x = 39
x = 1
To chech: 5(7x+5)3−233=13−4x−23for x=1
L.H.S.=5(7x+5)3−233
=35x+253−233
=35(1)+253−233
=603−233
=60−233
=373
R.H.S.=13−4x−23
=13−4(1)−23
=13−23
=39−23
=373
∴L.H.S.=R.H.S.
Hence, the given equation is verified for x= 1.