Question

Solve each of the following equations and check your answers:
$\frac{x-3}{5}-2=-1$

Answer 1

$\frac{x-3}{5}-2=-1$
Adding 2 to both sides, we get
⇒ $\frac{x-3}{5}-2+2=-1+2$
⇒ $\frac{x-3}{5}=1$
Multiplying both sides by 5, we get
⇒ $\left(\frac{x-3}{5}\right)\times 5=1\times 5$
⇒ x $-$ 3 = 5
Adding 3 to both sides, we get
⇒ x $-$ 3 + 3 = 5 + 3
⇒ x = 8
Verification:
Substituting x = 8 in LHS, we get
= $\frac{8-3}{5}-2$
= $\frac{5}{5}-2$
= 1 $-$ 2
= $-$1
= RHS
LHS = RHS
Hence, verified.