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Question

Solve each of the following equations by the trial-and-error method:
(i) y + 9 = 13
(ii) x − 7 = 10
(iii) 4x = 28
(iv) 3y = 36
(v) 11 + x = 19
(vi) x3=4
(vii) 2x − 3 = 9
(viii) 12x + 7 = 11
(ix) 2y + 4 = 3y
(x) z − 3 = 2z − 5

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Solution

(i) y + 9 = 13
We try several values of y until we get the L.H.S. equal to the R.H.S.
y L.H.S. R.H.S. Is LHS =RHS ?
1 1 + 9 = 10 13 No
2 2 + 9 = 11 13 No
3 3 + 9 = 12 13 No
4 4 + 9 = 13 13 Yes
∴ y = 4

(ii) x − 7= 10
We try several values of x until we get the L.H.S. equal to the R.H.S.
x L.H.S. R.H.S. Is L.H.S. = R.H.S.?
10 10 − 7 = 3 10 No
11 11 − 7 = 4 10 No
12 12 − 7 = 5 10 No
13 13 − 7 = 6 10 No
14 14 − 7 = 7 10 No
15 15 − 7 = 8 10 No
16 16 − 7 = 9 10 No
17 17 − 7 = 10 10 Yes

∴ x = 17

(iii) 4x = 28
We try several values of x until we get the L.H.S. equal to the R.H.S.
x L.H.S. R.H.S. Is L.H.S. = R.H.S.?
1 4 × 1 = 4 28 No
2 4 × 2 = 8 28 No
3 4 × 3 = 12 28 No
4 4 × 4 = 16 28 No
5 4 × 5 = 20 28 No
6 4 × 6 = 24 28 No
7 4 × 7 = 28 28 Yes
∴ x = 7

(iv) 3y = 36
We try several values of x until we get the L.H.S. equal to the R.H.S.
y L.H.S. R.H.S. Is L.H.S. = R.H.S.?
6 3 × 6 = 18 36 No
7 3 × 7 = 21 36 No
8 3 × 8 = 24 36 No
9 3 × 9 = 27 36 No
10 3 × 10 = 30 36 No
11 3 ×11 = 33 36 No
12 3 × 12 = 36 36 Yes
∴ y = 12

(v) 11 + x = 19
We try several values of x until we get the L.H.S. equal to the R.H.S.
x L.H.S. R.H.S. Is L.H.S. = R.H.S.?
1 11 + 1 = 12 19 No
2 11 + 2 = 13 19 No
3 11 + 3 = 14 19 No
4 11 + 4 = 15 19 No
5 11 + 5 = 16 19 No
6 11 + 6 = 17 19 No
7 11 + 7 = 18 19 No
8 11 + 8 = 19 19 Yes
∴ x = 8

(vi) x3 = 4
Since R.H.S. is an natural number so L.H.S. must also be a natural number. Thus, x has to be a multiple of 3.
x L.H.S. R.H.S. Is L.H.S. = R.H.S.?
3 33=1 4 No
6 63=2 4 No
9 93=3 4 No
12 123=4 4 Yes
∴ x = 12

(vii) 2x − 3 = 9

We try several values of x until we get the L.H.S. equal to the R.H.S.
x L.H.S. R.H.S. Is L.H.S. = R.H.S.?
1 2 × 1 − 3 = −1 9 No
2 2 × 2 − 3 = 1 9 No
3 2 × 3 − 3 = 3 9 No
4 2 × 4 − 3 = 5 9 No
5 2 × 5 − 3 = 7 9 No
6 2 × 6 − 3 = 9 9 Yes
∴ x = 6

(viii) 12x + 7 = 11
Since, R.H.S. is a natural number so L.H.S. must be a natural number Thus, we will try values if x which are multiples of 'x'
x L.H.S. R.H.S. Is L.H.S. = R.H.S.?
2 2/2 + 7 = 8 11 No
4 4/2 + 7 = 9 11 No
6 6/2 + 7 = 10 11 No
8 8/2 + 7 = 11 11 Yes
∴ x = 8

(ix) 2y + 4 = 3y
We try several values of y until we get the L.H.S. equal to the R.H.S.
y L.H.S. R.H.S. Is L.H.S. = R.H.S.?
1 2 × 1 + 4 = 6 3 × 1 = 3 No
2 2 × 2 + 4 = 8 3 × 2 = 6 No
3 2 × 3 + 4 = 10 3 × 3 = 9 No
4 2 × 4 + 4 = 12 3 × 4 = 12 Yes
∴ y = 4

(x) z − 3 = 2z − 5
We try several values of z till we get the L.H.S. equal to the R.H.S.
z L.H.S. R.H.S. Is L.H.S. = R.H.S.?
1 1 − 3 = −2 2 × 1 − 5 = −3 No
2 2 − 3 = −1 2 × 2 − 5 = −1 Yes
∴ z = 2

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