Question

Solve each of the following equations by trial and error method:

(ii) $2x+1=7$

Answer 1

Put different values of $x$ in such a way that L.H.S = R.H.S

Let us put $x=1$ in $2x+1$, we have

$2\times 1+1=3$ which is not equal to $7$

So, $x=1$ is not the solution of given equation.

Let us put $x=2$ in $2x+1$, we have

$2\times 2+1=5$ which is not equal to $7$

So, $x=2$ is not the solution of given equation.

Let us put $x=3$ in $2x+1$, we have

$2\times 3+1$ which is equal to $7$

So, $x=3$ is the solution of given equation.

Hence, By Hit and trial method $x=3$ is the solution of given equation.