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Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
Solve each of...
Question
Solve each of the following equations by trial-and-error method:
x
−
7
=
10
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Solution
Given the equation is
x
−
7
=
10
.....(1).
Now by guessing put
x
=
16
in (1) then we get,
16
−
7
=
9
, which is close to
10
.
Now put
x
=
17
in (1) then we get,
17
−
7
=
10
, which is required.
So
x
=
17
is the correct solution.
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