Question

Solve each of the following equations by using inverse operations.

$a+3\frac{1}{2}=5$

Answer 1

$$\begin{gathered} \Rightarrow \mathrm{a}+3\frac{1}{2}=5 \\ \Rightarrow \mathrm{a}+\frac{7}{2}=5 \end{gathered}$$

Adding $-\frac{7}{2}\mathrm{on}\mathrm{both}\mathrm{sides}$

$$\begin{gathered} \Rightarrow a+\frac{7}{2}+\left(-\frac{7}{2}\right)=5+\left(-\frac{7}{2}\right) \\ \Rightarrow a+\frac{7}{2}-\frac{7}{2}=5-\frac{7}{2} \\ \Rightarrow a=\frac{10-7}{2} \\ \Rightarrow a=\frac{3}{2} \end{gathered}$$

Hence, the solution is $a=\frac{3}{2}$