Question

Solve each of the following equations by using the method of completing the square:
$4x^2+4bx-(a^2-b^2)=0$

Answer 1

$4x^2+4bx-(a^2-b^2)=0$

$4x^2+4bx-a^2+b^2=0$

$(2x{)}^2+2.(2x).b+b^2-a^2=0$

$(2x+b{)}^2-a^2=0$

use formula,

$a^2-b^2=(a-b)(a+b)$

$(2x+b-a)(2x+b+a)=0$

$x=\frac{(a-b)}{2},-\frac{(a+b)}{2}$