Solve each of the following equations by using the method of completing the square:
$x^{2} - 4 x + 1 = 0$

Open in App

Solution

$x^{2} - 4 x + 1 = 0 x^{2} - 4 x = - 1 x^{2} - 4 x + 2^{2} = - 1 + 2^{2} (x - 2)^{2} = - 1 + 4 (x - 2)^{2} = 3 x - 2 = \pm \sqrt{3} x = 2 \pm \sqrt{3}$

So the value of x are $2 + \sqrt{3} o r 2 - \sqrt{3}$

Suggest Corrections

Similar questions

x^{2} - 4 x + 1 = 0

Solve each of the following equations by using the method of completing the square:
$x^{2} - (\sqrt{2} + 1) x + \sqrt{2} = 0$

x^{2} - 4 x + 1 = 0

4 x^{2} + 4 b x - (a^{2} - b^{2}) = 0

4 x^{2} + 4 \sqrt{3} x + 3 = 0

Join BYJU'S Learning Program