Solve each of the following equations by using the method of completing the square:
$x^{2} - 6 x + 3 = 0$

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Solution

$x^{2} - 6 x + 3 = 0 x^{2} - 6 x = - 3 x^{2} - 6 x + 3^{2} = - 3 + 3^{2} (x - 3)^{2} = - 3 + 9 (x - 3)^{2} = 6 x - 3 = \pm \sqrt{6} x = 3 \pm \sqrt{6}$

So the value of x are $3 + \sqrt{6} o r 3 - \sqrt{6}$

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