Question

Solve the following equation when $0^{\circ }<\theta <{90}^{\circ }$
$3{\tan }^2\theta -1=0$

Answer 1

We have,
$3{\tan }^2\theta =1$
$\Rightarrow {\tan }^2\theta =\frac{1}{3}$

$\Rightarrow \tan \theta =\frac{1}{\sqrt{3}}$

$\Rightarrow \tan \theta =\tan {30}^{\circ }$

$\Rightarrow \theta ={30}^{\circ }$