Solve each of the following quadratic equations:

(2x − 3)(3x + 1) = 0

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Solution

(2x − 3)(3x + 1) = 0

⇒ 2x − 3 = 0 or 3x + 1 = 0

⇒ 2x = 3 or 3x = −1

⇒ x = $\frac{3}{2}$ or x = $- \frac{1}{3}$

Hence, the roots of the given equation are $\frac{3}{2}$ and $- \frac{1}{3}$ .

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