Question

Solve each of the following quadratic equations:
$48x^2-13x-1=0$

Answer 1

$48x^2-13x-1=0$

$=48x^2-16x+3x-1=0$

$=16x(3x-1)+1(3x-1)=0$

$=(3x-1)(16x+1)=0$

$3x-1=0$
$x=1/3$
and
$16x+1=0$
$x=-1/16$