Question

Solve each of the following quadratic equations:
$6x^2+11x+3=0$

Answer 1

$6x^2+11x+3=0$

$6x^2+(9+2)x+3=0$

$6x^2+9x+2x+3=0$

$3x(2x+3)+1(2x+3)=0$

$(2x+3)(3x+1)=0$

when
$2x+3=0$ then
$x=\left(\frac{-3}{2}\right)$

and $3x+1=0$
$x=\left(\frac{-1}{3}\right)$

so $x=\left(\frac{-3}{2}\right)and\left(\frac{-1}{3}\right)$