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Question

Solve each of the following quadratic equations:
1x2+2x1=6x,x0,1,2

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Solution

1x2+2x1=6x

1(x1)+2(x2)x2x2x+2=6x

x1+2x4x23x+2=6x

3x5x23x+2=6x

3x25x=6x218x+12

6x23x218x+5x+12=0

3x213x+12=0

3x29x4x+12=0

3x(x3)4(x3)=0

(3x4)(x3)=0

x=3 or 43


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