wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve each of the following quadratic equations:

x-1x-2+x-3x-4=313, x2, 4 [CBSE 2010]

Open in App
Solution

x-1x-2+x-3x-4=313, x2, 4x-1x-4+x-2x-3x-2x-4=103x2-5x+4+x2-5x+6x2-6x+8=1032x2-10x+10x2-6x+8=103
x2-5x+5x2-6x+8=533x2-15x+15=5x2-30x+402x2-15x+25=02x2-10x-5x+25=0
2xx-5-5x-5=0x-52x-5=0x-5=0 or 2x-5=0x=5 or x=52
Hence, 5 and 52 are the roots of the given equation.

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Quadratic Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon