Solve each of the following quadratic equations:
$x^{2} + 2 \sqrt{2} x - 6 = 0$

Open in App

Solution

$x^{2} + 2 \sqrt 2 x - 6 = 0$

By factorization

$x^{2} + 3 \sqrt 2 x - \sqrt 2 x - 6 = 0$

$x (x + 3 \sqrt 2) - \sqrt 2 (x + 3 \sqrt 2) = 0$

$(x - \sqrt 2) (x + 3 \sqrt 2) = 0$

Ans. $x = \sqrt 2 a n d x = - 3 \sqrt 2$

Suggest Corrections

606

Similar questions

x^{2} - (1 + \sqrt{2}) x + \sqrt{2} = 0

x^{2} + 5 x - (a^{2} + a - 6) = 0

x^{2} + 6 x + 5 = 0

Solve the following quadratic equation:
$x^{2} - 3 \sqrt{5} x + 10 = 0$

x^{2} - 2 a x - (4 b^{2} - a^{2}) = 0

Join BYJU'S Learning Program