Solve each of the following quadratic equations:
$x^{2} + 2 \sqrt{2} x - 6 = 0$

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Solution

$x^{2} + 2 \sqrt 2 x - 6 = 0$

By factorization

$x^{2} + 3 \sqrt 2 x - \sqrt 2 x - 6 = 0$

$x (x + 3 \sqrt 2) - \sqrt 2 (x + 3 \sqrt 2) = 0$

$(x - \sqrt 2) (x + 3 \sqrt 2) = 0$

Ans. $x = \sqrt 2 a n d x = - 3 \sqrt 2$

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