Solve each of the following system of equations graphically:
$x + 2 y + 2 = 0$
$3 x + 2 y - 2 = 0$

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Solution

$x + 2 y + 2 = 0$ ....(1)
$3 x + 2 y - 2 = 0$ ......(2)

Isolate $x$ from equation (1) and find the value of $x$ and $y$ .
$x + 2 y + 2 = 0$
or $x = - 2 y - 2$

$x :$ $- 2$ $0$ $2$
$y :$ $0$ $- 1$ $- 2$

Similarly, isolate $x$ from equation (2) and find the values of $x$ and $y$ .

$3 x + 2 y - 2 = 0$
or $x = (2 - 2 y) / 3$

$x :$ $0$ $2$ $- 2$
$y :$ $1$ $- 2$ $4$

Graph:

As expressed in above graph where red line=> $x + 2 y + 2 = 0$ & blue line => $3 x + 2 y - 2 = 0$
Both the lines intersect each other at point $(2, - 2)$ .
So, $x = 2, y = - 2$

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