Solve each of the following systems of equations by the method of cross-multiplication:

$(a - b) x + (a + b) y = 2 a^{2} - 2 b^{2}$

$(a + b) (x + y) = 4 a b$

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Solution

$x = \frac{2 a b - a^{2} + b^{2}}{b}, y = \frac{(a - b) (a^{2} + b^{2})}{b (a + b)}$

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Similar questions

(a - b) x + (a + b) y = 2 a^{2} - 2 b^{2}

(a + b) (x + y) = 4 a b

Solve the equation by substitution method :

(a+b)x + (a+b)y = 2a² -2b²

(a+b) (x + y) = 4ab

x (a - b + \frac{a b}{a - b}) = y (a + b - \frac{a b}{a + b}) x + y = 2 a^{2}

Solve each of the following systems of equations by the method of cross-multiplication:

$x (a - b + \frac{a b}{a - b}) = y (a + b - \frac{a b}{a + b})$

$x + y = 2 a^{2}$

(a - b) x + (a + b) y = 2 (a^{2} - b^{2})

(a + b) x - (a - b) y = 4 a b

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