Solve each of the following systems of equations by the method of cross-multiplication:

$\frac{a^{2}}{x} - \frac{b^{2}}{y} = 0$

$\frac{a^{2} b}{x} + \frac{b^{2} a}{y} = a + b, x, y \neq 0$

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Solution

$x = a^{2}, y = b^{2}$

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Similar questions

\frac{a^{2}}{x} - \frac{b^{2}}{y} = 0

\frac{a^{2} b}{x} + \frac{b^{2} a}{y} = a + b, x, y \neq 0

\frac{x}{a} + \frac{y}{b} = a + b

\frac{x}{a^{2}} + \frac{y}{b^{2}} = 2

\frac{a^{2}}{x} - \frac{b^{2}}{y} = 0 \frac{a^{2} b}{x} + \frac{b^{2} a}{y} = a + b, x, y \neq 0

Solve each of the following systems of equations by using the method of cross multiplication:

$\frac{a}{x} - \frac{b}{y} = 0, \frac{a b^{2}}{x} + \frac{a^{2} b}{y} = (a^{2} + b^{2}), w h e r e x \neq 0 a n d y \neq 0.$

\frac{x + y}{x y} = 2, \frac{x - y}{x y} = 6

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