Solve equation, given below, using factorisation method:
2(x2−6)=3(x−4)
Given, 2(x2−6)=3(x−4)⇒2x2−12=3x−12⇒2x2−3x=0⇒x(2x−3)=0⇒x=0 or x=32
(2x−3)2=49
(x+3)2−4(x+3)−5=0
2x2−9x+10=0,when(i) xϵ N (ii) xϵ Q.
5x−2−3x+6=4x
6x=1+x