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Question

Solve equation, given below, using factorisation method:

2x29x+10=0,when(i) xϵ N (ii) xϵ Q.

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Solution

Given
2 x squared minus 5 x minus 4 x plus 10 equals 0 x open parentheses 2 x minus 5 close parentheses minus 2 open parentheses 2 x minus 5 close parentheses equals 0 open parentheses x minus 2 close parentheses open parentheses 2 x minus 5 close parentheses equals 0 x equals 2 x equals 5 over 2 f o r space x element of N x equals 2 f o r space X element of Q X equals 2 X equals 5 over 2


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