wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve equation, given below, using factorisation method:

5x23x+6=4x

Open in App
Solution

5x23x+6=4x5(x+6)3(x2)(x2)(x+6)=4x5x+303x+6x2+4x12=4x2x+36x2+4x12=4x2x2+36x=4x2+16x482x220x48=0x210x24=0x212x+2x24=0x(x12)+2(x12)=0(x12)(x+2)=0x=12 or x=2


flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving QE by Factorisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon