Solve equation, given below, using factorisation method:

$\frac{6}{x} = 1 + x$

Open in App

Solution

Given, $\frac{6}{x} = 1 + x \Rightarrow 6 = x + x^{2} \Rightarrow x^{2} + x - 6 = 0 \Rightarrow x^{2} + 3 x - 2 x - 6 = 0 \Rightarrow x (x + 3) - 2 (x + 3) = 0 \Rightarrow (x + 3) (x - 2) = 0 \Rightarrow x = - 3 o r x = 2$

Suggest Corrections

Similar questions

Solve equation, given below, using factorisation method:

$\frac{5}{x - 2} - \frac{3}{x + 6} = \frac{4}{x}$

Solve equation, given below, using factorisation method:

$x = \frac{3 x + 1}{4 x}$

Solve equation, given below, using factorisation method:

$(1 + \frac{1}{x + 1}) (1 - \frac{1}{x - 1}) = \frac{7}{8}$

Solve equation, given below, using factorisation method:

$x (x - 5) = 24$

Solve equation,number 1 to 20 ,given below, using factorisation method:

$(x + 1) (2 x + 8) = (x + 7) (x + 3)$

Join BYJU'S Learning Program