Solve equations using substitution method:
$3 x + 2 y = 1$ and $2 x - 3 y = 5$

1

and

- 1

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1

and

1

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- 1

and

- 1

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1

and

\frac{1}{2}

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Solution

The correct option is A $1$ and $- 1$
$3 x + 2 y = 1$ ------- (1)
$2 x - 3 y = 5$ ------ (2)
From equation 1:
$2 y = 13 x$
$2 y = 1 - 3 x$
$Y = \frac{1 - 3 x}{2}$
Substitute the value of y in equation 2:
$2 x - 3 y = 5$
$2 x 3 (\frac{1 - 3 x}{2}) = 5$
$4 x 3 + 9 x = 10$
$13 x = 10 + 3$
$X = \frac{13}{13} = 1$
Now, Substitute $x = 1$ in equation 1 :
$3 x + 2 y = 1$
$3 x 1 + 2 y = 1$
$2 y = 13$
$Y = \frac{- 2}{2}$
$Y = - 1$
Therefore the solution is: $x = 1$ and $y = - 1$

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